DESCRIPTION:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in. Additionally, if the number is negative, return 0 (for languages that do have them).
Note: If the number is a multiple of both 3 and 5, only count it once.
Courtesy of projecteuler.net (Problem 1)
int solution(int number)
{
if (number < 3)
return 0;
else {
int sum = 0;
for (int i = 3; i < number; i++) {
if (i % 3 == 0 || i % 5 == 0)
sum += i;
}
return sum;
}
}